recursively count the words occurrence in the text files
Shahar Dag
dag at cs.technion.ac.il
Sun Jan 2 11:52:49 UTC 2011
----- Original Message -----
From: "S Mathias" <smathias1972 at yahoo.com>
To: <ubuntu-users at lists.ubuntu.com>
Sent: Thursday, December 30, 2010 8:34 PM
Subject: recursively count the words occurrence in the text files
>I just can't google for it:
>
> I'm searching for a "bash" "one liner" (awk, perl, or anything) for this:
>
> there are text files, in several directories:
>
> mkdir one
> mkdir two
> mkdir three
>
> echo "word1 word2 word3" > one/asf.txt
> echo "word2 word4, word5" > one/asfcxv saf.txt
> echo "word1. word2" > one/dsgsdg.txt
>
> echo "word6, word3!" > two/sdgsd dsf.txt
> echo "word6" > two/ergd.txt
>
> echo "asdf, word2" > three/werdf.txt
> echo "word7, word8 word9 word10" > three/qwerb erfsdgdsg.txt
> echo "word4 word3" > three/web erg as.txt
>
> so it does the magic* "recursively":
>
> $ SOMEMAGIC > output.txt
> cat output.txt
> asdf 1
> word1 2
> word2 4
> word3 3
> word4 2
> word5 1
> word6 2
> word7 1
> word8 1
> word9 1
> word10 1
> $
>
>
>
> *recursively count the words occurrence in the text files like: "word1 2"
> can anyone point to a howto/link? [re: i just can't google for it :\]
>
>
>
>
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>
write an awk program that keeps a table with all the words it gets and
another table (hash table) that counts how many time each word appear
good luck
Shahar
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