Ubuntu-Chicago Parsing argv in C++
Eric O'Neal
fyedernoggersnodden at gmail.com
Mon Sep 11 02:39:36 BST 2006
Heya, I was hoping you guys could help me with some novice programming
woes. I'm trying to parse command-line options (I want to write the parser
myself for the experience), and somehow am stuck up on... well... I dunno,
but it's not working.
The logic in my code is comparable to the following sample:
---------------------------
#include <iostream>
using namespace std;
int main( int argc, char *argv[] )
{
for (int i = 1; i < argc; i++)
{
cout << "*Debug: Parsing(" << argv[i] << ")" << endl;
if (argv[i] == "greetings")
{
cout << "Found: greetings" << endl;
}
else if (argv[i] == "g")
{
cout << "Found: g" << endl;
}
else
{
cout << "Invalid" << endl;
}
}
return 0;
}
---------------------------
The above compiles fine with GCC v4.0.1 into a binary named "sandbox". But
when I run it:
---------------------------
$ ./sandbox greetings
*Debug: Parsing(greetings)
Invalid
*Debug: Parsing(g)
Invalid
---------------------------
I though I had something working earlier, but whatever I changed broke it.
Help?
SigmaX
--
My home page: http://www.SigmaX.org
"ttocs laeno cire oshkosh b'gosh fyedernoggersnodden nicht stein bon
probiscus"
"Education is what remains after one has forgotten everything he learned in
school"
-- Albert Einstein
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