awk and filenames with spaces.....

[Tony Arnold]

Chris,

David Koski wrote:
> I don't know about awk but this works although there is probably a better
> way:
> 
> unzip -qql myzipfile.zip \
> 	| while read line; \
> 	do name=$(echo $line \
> 	| sed 's/^[^      ]*[     ]*[^    ]*[     ]*[^    ]*//'); \
> 	echo $name; done

You could also try using the cut command as follows:

	unzip -l myfile.zip | cut -c 29-

which outputs from the 29th character onwards. Fortunately, unzip seems
to use fixed widths for its columns!

Regards,
Tony.

> On Monday 21 May 2007 02:19, Chris Malton wrote:
>> Hi,
>>
>> I'm trying to use awk in combination with unzip -l to list all the
>> filenames in a zip archive.  The problem comes when there's a apce in
>> the filename, as unzip uses spaces as separators.  How can I get awk to
>> print from a particular index onwards?  Something like printing all
>> fields higher than index 4, for example.
>>
>> Any ideas how?
>>
>> Chris
> 
> 

-- 
Tony Arnold, IT Security Coordinator, University of Manchester,
IT Services Division, Kilburn Building, Oxford Road, Manchester M13 9PL.
T: +44 (0)161 275 6093, F: +44 (0)870 136 1004, M: +44 (0)773 330 0039
E: tony.arnold at manchester.ac.uk, H: http://www.man.ac.uk/Tony.Arnold