[Bug 485225] [NEW] Won't link when using ftglGetLayoutBBox

Launchpad Bug Tracker 485225 at bugs.launchpad.net
Tue Apr 13 13:55:16 UTC 2010

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Description:	Ubuntu 9.10
Release:	9.10
  Installed: 2.1.3~rc5-2
  Candidate: 2.1.3~rc5-2
  Version table:
 *** 2.1.3~rc5-2 0
        500 http://us.archive.ubuntu.com karmic/universe Packages
        100 /var/lib/dpkg/status

When it try to compile an example that tries to call ftglGetLayoutBBox I
get a link error.

$ cat example.c 
#include <FTGL/ftgl.h>
int main(int argc, char **argv) {
    float bbox[6];
    ftglGetLayoutBBox(NULL, "Hello, world!", bbox);
    return 0;
$ gcc $(pkg-config --cflags --libs ftgl freetype2) -lglut example.c &&./a.out 
/tmp/cc8b7sZG.o: In function `main':
example.c:(.text+0x21): undefined reference to `ftglGetLayoutBBox'
collect2: ld returned 1 exit status

However the expected result is
$ gcc $(pkg-config --cflags --libs ftgl freetype2) -lglut example.c &&./a.out 
FTGL warning: NULL pointer in _ftglGetLayoutBBox

The bug is caused by a discrepancy between the function name in the
header and library.

    $ readelf -s /usr/lib/libftgl.so|grep LayoutBBox
       579: 0000000000023bf0   313 FUNC    GLOBAL DEFAULT   11 ftgGetlLayoutBBox

    $ grep GetLayoutBBox /usr/include/FTGL/FTLayout.h
    FTGL_EXPORT void ftglGetLayoutBBox(FTGLlayout *layout, const char* string,

Readelf shows that the function is named incorrectly
(ftgGetlLayoutBBox), but the header FTLayout.h declared the function as

** Affects: ftgl (Ubuntu)
     Importance: Undecided
     Assignee: MOTU (motu)
         Status: New

Won't link when using ftglGetLayoutBBox
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