[Bug 485225] Re: Won't link when using ftglGetLayoutBBox

[Flameass]

** Description changed:

  Description:	Ubuntu 9.10
  Release:	9.10
  libftgl2:
-   Installed: 2.1.3~rc5-2
-   Candidate: 2.1.3~rc5-2
-   Version table:
-  *** 2.1.3~rc5-2 0
-         500 http://us.archive.ubuntu.com karmic/universe Packages
-         100 /var/lib/dpkg/status
- libftgl2:
-   Installed: 2.1.3~rc5-2
-   Candidate: 2.1.3~rc5-2
-   Version table:
-  *** 2.1.3~rc5-2 0
-         500 http://us.archive.ubuntu.com karmic/universe Packages
-         100 /var/lib/dpkg/status
+   Installed: 2.1.3~rc5-2
+   Candidate: 2.1.3~rc5-2
+   Version table:
+  *** 2.1.3~rc5-2 0
+         500 http://us.archive.ubuntu.com karmic/universe Packages
+         100 /var/lib/dpkg/status
  
+ When it try to compile an example that tries to call ftglGetLayoutBBox I
+ get a link error.
  
- When using the C interface function ftglGetLayoutBBox, the function is not found in the library.
+ $ cat example.c 
+ #include <FTGL/ftgl.h>
+ int main(int argc, char **argv) {
+     float bbox[6];
+     ftglGetLayoutBBox(NULL, "Hello, world!", bbox);
+     return 0;
+ }
+ $ gcc $(pkg-config --cflags --libs ftgl freetype2) -lglut example.c &&./a.out 
+ /tmp/cc8b7sZG.o: In function `main':
+ example.c:(.text+0x21): undefined reference to `ftglGetLayoutBBox'
+ collect2: ld returned 1 exit status
  
-     $ readelf -s /usr/lib/libftgl.so|grep LayoutBBox
-        579: 0000000000023bf0   313 FUNC    GLOBAL DEFAULT   11 ftgGetlLayoutBBox
+ However the expected result is
+ $ gcc $(pkg-config --cflags --libs ftgl freetype2) -lglut example.c &&./a.out 
+ FTGL warning: NULL pointer in _ftglGetLayoutBBox
  
-     $ grep GetLayoutBBox /usr/include/FTGL/FTLayout.h
-     FTGL_EXPORT void ftglGetLayoutBBox(FTGLlayout *layout, const char* string,
+ The bug is caused by a discrepancy between the function name in the
+ header and library.
+ 
+     $ readelf -s /usr/lib/libftgl.so|grep LayoutBBox
+        579: 0000000000023bf0   313 FUNC    GLOBAL DEFAULT   11 ftgGetlLayoutBBox
+ 
+     $ grep GetLayoutBBox /usr/include/FTGL/FTLayout.h
+     FTGL_EXPORT void ftglGetLayoutBBox(FTGLlayout *layout, const char* string,
  
  Readelf shows that the function is named incorrectly
  (ftgGetlLayoutBBox), but the header FTLayout.h declared the function as
  ftglGetLayoutBBox.

-- 
Won't link when using ftglGetLayoutBBox
https://bugs.launchpad.net/bugs/485225
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