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Ed Greshko wrote:
<blockquote cite="mid:47A7DB69.4070305@greshko.com" type="cite">
<pre wrap="">Willis Taylor wrote:
</pre>
<blockquote type="cite">
<pre wrap="">It's true that I did not like it but I did listen and I put the other
modem in place but I no sooner set it up to connect with my server than
it failed.
I'm down to learning how to put a router? in between the #1 & #2
computers and then connecting it to the ethernet connection on the
Modem/Router or I'll need to purchase a Wireless card to connect the #1
computer to the 2Wire. I have looked on ebay and it looks like I can
pick up a PCI Wireless 802.11g for less than 20 dollars and I'll likely
go that way because I just have no idea how to put a four port into the
system and set it up.
So thank you to each and everyone of you. I apologize for being such a
problem. I'll try to research this 4 port deal but if I fail to learn
that I'll likeky go with the wireless pci card.
</pre>
</blockquote>
<pre wrap=""><!---->
It sounds like your 2Wire gateway has a single ethernet connection but that
both of your systems are within reach of the gateway and they both have
ethernet adapters.
If that is the case, there is no need to go wireless.
Simply get a 4-port ethernet switch...sometimes still called a hub...then
connect your 2wire gateway's ethernet connection to a port on the switch and
the other computers to other available ports.
There is no "routing" going on. Basically, the switch makes it such that it
appears to #1 and #2 that they have their own individual connection to the
2wire.
With a switch there is no configuration. Makes life simple.
</pre>
</blockquote>
<font size="+2"><font face="Times New Roman, Times, serif">I read your
reply and went to ebay and bought a linksys 5 port and 2 five foot cat
5e cords for just over $13US. I'll have them in here is about a week.
Thank you bery much because last week I purchased a KVM switch and the
computers will be less than 3 foot apart as soon as it comes in later
this week.<br>
<br>
Once more, thank you very much!<br>
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