Removing all at jobs except the ones running?

[Karl Auer]

On Mon, 2022-03-07 at 09:12 +0100, Bo Berglund wrote:
> I am scheduling jobs to be executed using at and this works fine
> mostly.
> 
> But sometimes I want to reset the at job list and I have found this
> command to
> ease this when the at job list is long:
> 
> atq | cut -f 1 | xargs atrm
> [...]
> But since atq lists also the *running* jobs it will attempt to remove
> also these, which I don't want.
> How can I exclude running jobs from removal while still being able to
> remove all queued jobs easily?

atq lists all jobs by default, but you can limit the output to a named
queue. If you specify the special queue-name "=" it will list only
running jobs. So if you combine the list of all jobs and the list of
running jobs, then use sort and "uniq -u" to remove any jobs that
appear twice, you should get a list of non-running jobs that you can
pump into xargs.

Of course, any job can go from running to non-running at any moment, or
vice versa.

Be warned that I have not tried this myself!

Regards, K.


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Karl Auer (kauer at biplane.com.au)
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