How to pass * as part of argument string to script?

[Karl Auer]

On Thu, 2021-08-26 at 14:12 +0200, Bo Berglund wrote:
> This is why my script prunelist is so elaborate because it lists the
> *older* files to remove.

Then skip the last part of the list instead of the first:

   #!/bin/sh
   SKIP=$1
   shift
   N=`expr $# - $SKIP`
   FTR=`echo $* | tr " "  "\n" | head -n $N`
   rm $FTR

"FTR" means "Files To Remove" :-)

"tr" replaces spaces with newlines so head sees a list of lines.

Regards, K.

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Karl Auer (kauer at biplane.com.au)
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