awk getline to display first three lines in file

[Normand Marion]

http://www.gnu.org/software/gawk/manual/gawk.html

2016-01-01 8:47 GMT-05:00 asad <a.alii85 at gmail.com>:

> In your response, it only caters for single file not two?
>
> On Thu, Dec 31, 2015 at 4:06 AM, MR <mrzenwiz at gmail.com> wrote:
>
>>
>>
>> On Wed, Dec 30, 2015 at 11:03 AM, Normand Marion <
>> normand.marion at gmail.com> wrote:
>>
>>> 2015-12-29 10:12 GMT-05:00 asad <a.alii85 at gmail.com>:
>>>
>>>> I'm using
>>>>
>>>>     awk 'BEGIN {while((getline gf < "awk.script") > 0) {print gf}}'
>>>>
>>>> to read me first 3 three lines of the pattern. I can do with head -3 .
>>>> But I don't want to since, I have to switch lines between two files.
>>>>
>>>> Suppose awk.script contains
>>>>
>>>>
>>>>     line 1
>>>>     line 2
>>>>     line 3 <------- until here
>>>>     line 4
>>>>
>>>> I have tried updating the original cmd with this
>>>>
>>>>      awk 'BEGIN {while((getline gf < "awk.script") > 0) && f{print
>>>> $gf;f=0};NR<=3{f=1}}'
>>>>
>>>> the code is influenced from the examples give on link:-
>>>>
>>>> http://stackoverflow.com/questions/17908555/printing-with-sed-or-awk-a-line-following-a-matching-pattern
>>>>
>>>> error i'm getting is
>>>>
>>>>     awk: cmd. line:1: BEGIN {while((getline gf < "awk.script") > 0)
>>>> f{print $gf;f=0};NR<=3{f=1}}
>>>>     awk: cmd. line:1:                                                ^
>>>> syntax error
>>>>     awk: cmd. line:1: BEGIN {while((getline gf < "awk.script") > 0)
>>>> f{print $gf;f=0};NR<=3{f=1}}
>>>>     awk: cmd. line:1:
>>>>
>>>> How can it be done? thanks
>>>>
>>>> awk '{ if ( NR <= 3 ) print $0 }' your_file
>>
>> You can also do this to save time in case the file is large:
>>
>> awk '{print $0;} NR >= 3 { exit; }' your_file
>>
>>
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-- 
*Normand Marion*

normand.marion at gmail.com
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