awk getline to display first three lines in file

[asad]

I'm using

    awk 'BEGIN {while((getline gf < "awk.script") > 0) {print gf}}'

to read me first 3 three lines of the pattern. I can do with head -3 . But
I don't want to since, I have to switch lines between two files.

Suppose awk.script contains


    line 1
    line 2
    line 3 <------- until here
    line 4

I have tried updating the original cmd with this

     awk 'BEGIN {while((getline gf < "awk.script") > 0) && f{print
$gf;f=0};NR<=3{f=1}}'

the code is influenced from the examples give on link:-
http://stackoverflow.com/questions/17908555/printing-with-sed-or-awk-a-line-following-a-matching-pattern

error i'm getting is

    awk: cmd. line:1: BEGIN {while((getline gf < "awk.script") > 0) f{print
$gf;f=0};NR<=3{f=1}}
    awk: cmd. line:1:                                                ^
syntax error
    awk: cmd. line:1: BEGIN {while((getline gf < "awk.script") > 0) f{print
$gf;f=0};NR<=3{f=1}}
    awk: cmd. line:1:

How can it be done? thanks
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