Bash substitute gives unexpected results (?)

[Normand Marion]

^ Locates regular expression that follows at the beginning of line. The ^
is only special when it occurs at the beginning of the regular expression.

So in the sed command ^ followed by your range means that any of the [range
of characters] at the beginning of line never happened. ^ and /g are self
excluding

As I understand your expression as to remove '(|–' you should write

a="Black Sand Beach (ブラック・サンド・ビーチ)"; echo $a | sed 's/[(|–]//g'

2015-04-05 5:16 GMT-04:00 Nils Kassube <kassube at gmx.net>:

> Johnny Rosenberg wrote:
> > This is what I want. Everything except ”(” and ”–” (n-dash) should be
> > removed.
> > However, using pure Bash doesn't seem to work:
> >
> > $ a="Black Sand Beach (ブラック・サンド・ビーチ)"; echo ${a//[^(|–]}
> > (ブラック・サンド・ビーチ
> > $
> > Why does Bash consider n-dash and some Japanese characters the same?
>
> Maybe the three character encoding of your n-dash and the Japanese
> characters look similar enough to bash?
>
> > Is there a setting I need to do somehow?
>
> It has something to do with your locale settings. If you try the same
> with the default locale, the result is different. So I think you should
> set one of the LC_* shell variables (probably LC_COLLATE) to Japanese
> and try your command again.
>
>
> Nils
>
>
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-- 
*Normand Marion*

normand.marion at gmail.com
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