Help with a regular expression???
Amedee Van Gasse (ub)
amedee-ubuntu at amedee.be
Wed Jan 27 14:53:31 UTC 2010
On Wed, January 27, 2010 15:06, Kevin O'Gorman wrote:
> However that may be, I would suggest a perl filter, which is a one-liner
> suitable for a pipeline.
> perl -p -e 's/ ([^ ])/_ \1/g;'
> -p: copy everything in a loop
> -e: statement for the loop follows
> s/ / /g: do a substitution on everything (g=multiple times on a
> ( ): remember this
> [^ ]: a character class consisting of any one non-space character.
> Probably does not match newlines either.
> \1 : the first remembered thing
> Hope this helps.
The same regex syntax can be used with the bash command sed:
sed 's/ ([^ ])/_ \1/g'
This *may* be a bit faster than using heavyweight perl. OTOH perl can do a
lot more than sed, so it depends on what you want to do.
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