sed within `` in Bourn Shell isn't Working.

[Martin McCormick]

	I am doing something wrong but not sure what. This works
from the command line:

echo "ABC\DEF" | sed 's/\\//g'

	What you get is ABCDEF without the \ character.

	In a script, however, I am trying to replace the \ with
\\ and assign the output to a variable but the `` construct
seems to throw the whole thing off.

#! /bin/sh
uid=`echo "ABC\\DEF" | sed 's/\\/\\\\/g'`
echo $UID

I get an error like:

sed: -e expression #1, char 6: unterminated `s' command


	I have actually tried this same script on a FreeBSD
system. That version of sed echos back the whole command and
also complains about the unterminated s command. The second ' is
right next to the ` so I know it's there but the `statements`
must be confusing things.

	What am I missing here?

Thanks.

Martin McCormick WB5AGZ  Stillwater, OK 
Systems Engineer
OSU Information Technology Department Telecommunications Services Group