Variables in shell script not working

[Karl Auer]

On Sat, 2008-11-15 at 14:40 +0100, Jef Driesen wrote:
> If I quote the variable, the error disappears, but the rest of my
> script does not work anymore. No output is produced on stdout.
> Echo'ing the variable works, but the script does not seem to execute
> the contents of the variable when it reaches the line
> 
> $SOURCE | sed 's/foo/bar'

What happens? What output do you see, if any?

Does this script work?

   X="echo fred"
   $X | grep fred

It should output

   fred

If that works, try this:

   #!/bin/sh
   X="echo fred"
   $X | sed s/fred/martha/

It should output

   martha

If both those work, I suspect dos2unix does not output what you think it
outputs. As far as I can tell, dos2unix outputs nothing unless it has a
problem with a conversion (it converts in place by default), so I'm a
bit puzzled about what sed is supposed to be doing.

Regards, K.

-- 
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Karl Auer (kauer at biplane.com.au)                   +61-2-64957160 (h)
http://www.biplane.com.au/~kauer/                  +61-428-957160 (mob)

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