Bash Script

[Tony Arnold]

OOzy,

On Tue, 2006-10-24 at 13:53 +0300, OOzy Pal wrote:

> Num=$((Num+1));
> Num=$(printf %02d $Num)
> PROJECT=$Num-$PROJECT

Change this to:

Num=$((Num+1));
prefix=$(printf %02d $Num)
PROJECT=$prefix-$PROJECT

The problem is that $NUM has the leading zeros, so when it gets
substituted in the printf line, bash thinks it is an octal number,
because numbers starting with a zero are considered octal. By keeping
$NUM as just the number, you avoid this.

Regards,
Tony.
-- 
Tony Arnold, IT Security Coordinator, University of Manchester,
IT Services Division, Kilburn Building, Oxford Road, Manchester M13 9PL.
T: +44 (0)161 275 6093, F: +44 (0)870 136 1004, M: +44 (0)773 330 0039
E: tony.arnold at manchester.ac.uk, H: http://www.man.ac.uk/Tony.Arnold