<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta content="text/html;charset=ISO-8859-1" http-equiv="Content-Type"> </head> <body bgcolor="#ffffff" text="#000000"> Hi, I'm not 100% sure but this would make sense as the first answer to me: the machine with 990 ticks should be experiencing time at (990/1000) of real time the machine with 1015 ticks should be experiencing time at (1015/1000) of real time The length of time it would take the two systems to go out of sync be 5 seconds would be: (1015/1000)a - (990/1000)a = 5 where "a" is the time needed between syncs so answer is 200 seconds Sorry, but the I've not really got time to work out the second one right now. I'll try and get back to it at some point if someone hasn't beaten me to it ;-) Thanks Paul fatma oymak wrote: <blockquote cite="midBAY106-F4068E897731550724887DAB33C0@phx.gbl" type="cite"> <pre wrap="">Dear all, I have one problem....I couldnt find right answer...do you have any idea? please please let me know many thanks fatma "........Consider the behaviour of two machines in a distributed system. Both have clocks that are supposed to tick 1000 times per millisecond. One of them ticks 990 times per millisecond. The other ticks 1015 times per millisecond. If the system designer want to guarantee that clocks of these two machines never differ by more than 5 seconds, how often must be clocks be re-synchronized? Supposing that all machines in this distributed systems come from same manufacturer and the maximum drift rate is specified as 1.0%, how often must the clocks of this system must be re-synchonized if the system designers want to guarantee that clocks of these two machines never differ by more than 5 seconds? Describe in steps how you get your result......." _________________________________________________________________ Txt a lot? Get Messenger FREE on your mobile. <a class="moz-txt-link-freetext" href="https://livemessenger.mobile.uk.msn.com/">https://livemessenger.mobile.uk.msn.com/</a> </pre> </blockquote> <div class="moz-signature">-- <meta http-equiv="CONTENT-TYPE" content="text/html; "> <title></title> <meta name="GENERATOR" content="OpenOffice.org 1.1.4 (Win32)"> <meta name="AUTHOR" content="Paul Brunt"> <meta name="CREATED" content="20050208;16343548"> <meta name="CHANGEDBY" content="Paul Brunt"> <meta name="CHANGED" content="20050208;16392696"> <style>  </style> Paul Brunt Web Developer <a href="mailto:paul.brunt@armourhe.co.uk">paul.brunt@armourhe.co.uk</a> DDI +44 (0) 1279 719584 Stortford Hall Industrial Park Dunmow Road, Bishops Stortford, Hertfordshire, CM23 5GZ United Kingdom <a class="moz-txt-link-abbreviated" href="http://www.armourhe.co.uk">www.armourhe.co.uk</a> Tel +44 (0) 1279 501111 Fax +44 (0) 1279 501080 This message (including any attachments) is confidential and may be privileged. It is intended solely for the use of the individual or entity to whom they are addressed. If you are not the intended recipient, please e-mail the sender immediately by replying to this message and delete the material from any computer. Armour Home Electronics Ltd shall not be liable for the improper or incomplete transmission of the information contained in this communication nor for any delay in its receipt or damage to your system. Armour Home Electronics Ltd does not guarantee that the integrity of this communication has been maintained nor that this communication is free of viruses, interceptions or interference. This message is attributed to the sender and may not necessarily reflect the view of Armour Home Electronics Ltd. </div> </body> </html>