[Bug 663192] [NEW] Query with this_.id=? buggy
Ingo Busse
663192 at bugs.launchpad.net
Tue Oct 19 11:39:48 BST 2010
Public bug reported:
Ubuntu 10.10
mysql-server 5.1.49-1ubuntu8
Query delivers wrong result!
In Ubuntu 10.10 the attached query returns no result while in Ubuntu
10.04 with mysql-server 5.1.41 it properly returned the entry with
this_.id=1.
Note that when omitting the last part of the where clause (and
this_.id=1) the query correctly lists all entries. But when adding the
additional part to select a specific one nothing is returned.
select
this_.id as id61_1_,
aclkunde3_.akte_acl_kunde_id as akte1_3_,
aclkunde_a1_.id as kunde2_3_,
aclkunde_a1_.id as id13_0_,
aclkunde_a1_.kundennummer as kundennu3_13_0_,
aclkunde_a1_1_.anrede as anrede14_0_,
aclkunde_a1_1_.vorname as vorname14_0_,
aclkunde_a1_1_.zuname as zuname14_0_,
aclkunde_a1_2_.anrede as anrede15_0_,
aclkunde_a1_2_.vorname as vorname15_0_,
aclkunde_a1_2_.zuname as zuname15_0_,
case
when aclkunde_a1_1_.id is not null then 1
when aclkunde_a1_2_.id is not null then 2
when aclkunde_a1_.id is not null then 0
end as clazz_0_
from
akte this_
left outer join
akte_kunde aclkunde3_
on this_.id=aclkunde3_.akte_acl_kunde_id
left outer join
kunde aclkunde_a1_
on aclkunde3_.kunde_id=aclkunde_a1_.id
left outer join
anwalt aclkunde_a1_1_
on aclkunde_a1_.id=aclkunde_a1_1_.id
left outer join
kunde_glaeubiger aclkunde_a1_2_
on aclkunde_a1_.id=aclkunde_a1_2_.id
where
(
aclkunde_a1_.id=1
)
and this_.id=1;
** Affects: mysql-5.1 (Ubuntu)
Importance: Undecided
Status: New
--
Query with this_.id=? buggy
https://bugs.launchpad.net/bugs/663192
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