[Bug 1338382] Re: nmcli - Disconnect VPN Without Specifying ID or UUID
Lonnie Lee Best
1338382 at bugs.launchpad.net
Mon Jul 7 07:57:31 UTC 2014
If you are connected to a VPN, this command will return a list of established VPN connections:
nmcli con status | grep -oP '^(([^\s]+\s){1,}[\s]{2,}){4}yes.+$'
This command will list the IDs of any established vpn connections (one per line):
nmcli con status | grep -oP '^(([^\s]+\s){1,}[\s]{2,}){4}yes.+$' | grep -oP '^.*?(?=\s{2,})'
So to disconnect all VPN connections you could do it based on this ID like this:
nmcli con status | grep -oP '^(([^\s]+\s){1,}[\s]{2,}){4}yes.+$' | grep -oP '^.*?(?=\s{2,})' | sed 's/^/\x27/' | sed 's/$/\x27/' | xargs -L1 nmcli con down id
However, perhaps it is better to do this using the UUIDs.
You can list the UUIDs of all established VPN connections like this:
nmcli con status | grep -oP '^(([^\s]+\s){1,}[\s]{2,}){4}yes.+$' | grep -oP '(?<=[\s]{2})[^\s]+(?=(\s+[^\s]+){2}\s+yes.*)'
So you can disconnect all established VPN connections by UUID like this:
nmcli con status | grep -oP '^(([^\s]+\s){1,}[\s]{2,}){4}yes.+$' | grep -oP '(?<=[\s]{2})[^\s]+(?=(\s+[^\s]+){2}\s+yes.*)' | xargs -L1 nmcli con down uuid
Perhaps this logic could be added to nmcli, so that this following proposed option would concisely achieve the same results:
nmcli con down allvpn
--
You received this bug notification because you are a member of Network-
manager, which is subscribed to NetworkManager.
https://bugs.launchpad.net/bugs/1338382
Title:
nmcli - Disconnect VPN Without Specifying ID or UUID
To manage notifications about this bug go to:
https://bugs.launchpad.net/network-manager/+bug/1338382/+subscriptions
More information about the Ubuntu-reviews
mailing list