[Bug 1951155] [NEW] export i fails to work in bash

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Public bug reported:

I ran the following commands:
```
# In parent shell
export a=1
export i=2
bash # open child shell
# In child shell
echo $a # 1
echo $i # (empty)
exit
```

This bug happens when exporting the "i" variable from parent shell to child shell.
I have not tested what other variable names would trigger this bug.

* My OS: Ubuntu 20.04 LTS
* Bash version (running `bash --version`):
```
GNU bash, version 5.0.17(1)-release (x86_64-pc-linux-gnu)
Copyright (C) 2019 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>

This is free software; you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
```

I have also tested in the `sh` shell and did not see the problem:
```
# In parent shell
export a=1
export i=2
sh # open child shell
# In child shell
echo $a # 1
echo $i # 2
exit
```

** Affects: bash (Ubuntu)
     Importance: Undecided
         Status: New


** Tags: export

** Description changed:

  Try to run the following commands:
  ```
  # In parent shell
  export a=1
  export i=2
  bash # open child shell
  # In child shell
  echo $a # 1
  echo $i # (empty)
+ exit
  ```
  
  This bug happens when exporting the "i" variable from parent shell to child shell.
  I have not tested what other variable names would trigger this bug.
  
  * My OS: Ubuntu 20.04 LTS
  * Bash version (running `bash --version`):
  ```
  GNU bash, version 5.0.17(1)-release (x86_64-pc-linux-gnu)
  Copyright (C) 2019 Free Software Foundation, Inc.
  License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
  
  This is free software; you are free to change and redistribute it.
  There is NO WARRANTY, to the extent permitted by law.
  ```
+ 
+ I have also tested in the `sh` shell and did not see the problem:
+ ```
+ # In parent shell
+ export a=1
+ export i=2
+ sh # open child shell
+ # In child shell
+ echo $a # 1
+ echo $i # 2
+ exit
+ ```

** Description changed:

- Try to run the following commands:
+ I ran the following commands:
  ```
  # In parent shell
  export a=1
  export i=2
  bash # open child shell
  # In child shell
  echo $a # 1
  echo $i # (empty)
  exit
  ```
  
  This bug happens when exporting the "i" variable from parent shell to child shell.
  I have not tested what other variable names would trigger this bug.
  
  * My OS: Ubuntu 20.04 LTS
  * Bash version (running `bash --version`):
  ```
  GNU bash, version 5.0.17(1)-release (x86_64-pc-linux-gnu)
  Copyright (C) 2019 Free Software Foundation, Inc.
  License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
  
  This is free software; you are free to change and redistribute it.
  There is NO WARRANTY, to the extent permitted by law.
  ```
  
  I have also tested in the `sh` shell and did not see the problem:
  ```
  # In parent shell
  export a=1
  export i=2
  sh # open child shell
  # In child shell
  echo $a # 1
  echo $i # 2
  exit
  ```

-- 
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https://bugs.launchpad.net/bugs/1951155

Title:
  export i fails to work in bash

Status in bash package in Ubuntu:
  New

Bug description:
  I ran the following commands:
  ```
  # In parent shell
  export a=1
  export i=2
  bash # open child shell
  # In child shell
  echo $a # 1
  echo $i # (empty)
  exit
  ```

  This bug happens when exporting the "i" variable from parent shell to child shell.
  I have not tested what other variable names would trigger this bug.

  * My OS: Ubuntu 20.04 LTS
  * Bash version (running `bash --version`):
  ```
  GNU bash, version 5.0.17(1)-release (x86_64-pc-linux-gnu)
  Copyright (C) 2019 Free Software Foundation, Inc.
  License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>

  This is free software; you are free to change and redistribute it.
  There is NO WARRANTY, to the extent permitted by law.
  ```

  I have also tested in the `sh` shell and did not see the problem:
  ```
  # In parent shell
  export a=1
  export i=2
  sh # open child shell
  # In child shell
  echo $a # 1
  echo $i # 2
  exit
  ```

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