[Bug 1844518] Re: Ubuntu 19:10 - Python 3 os.path.isfile not working as expected
Brian Murray
brian at ubuntu.com
Thu Sep 19 10:13:11 UTC 2019
I'm not seeing this issue.
[ 3:12AM 10171 ] [ bdmurray at impulse:~/source-trees/command-not-found-extractor(locate✔) ]
$ python3
Python 3.7.4 (default, Jul 29 2019, 03:51:40)
[GCC 9.1.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import os
>>> os.path.isfile("/vmlinuz")
True
>>>
[ 3:12AM 10172 ] [ bdmurray at impulse:~/source-trees/command-not-found-extractor(locate✔) ]
$ apt-cache policy python3-minimal
python3-minimal:
Installed: 3.7.3-1
Candidate: 3.7.3-1
Could you provide some more details about the version of python3 which
you are using?
** Changed in: python3-defaults (Ubuntu)
Status: New => Incomplete
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https://bugs.launchpad.net/bugs/1844518
Title:
Ubuntu 19:10 - Python 3 os.path.isfile not working as expected
Status in python3-defaults package in Ubuntu:
Incomplete
Bug description:
When one runs "os.path.isfile("/vmlinuz")" or the same for
os.path.exists, False is returned. However, given the information at:
https://docs.python.org/3.8/library/os.path.html#os.path.isfile and
https://docs.python.org/3.7/library/os.path.html#os.path.isfile, True
should be returned for links as well.
"os.path.islink("/vmlinuz")" works as expected, so I'm not sure what's
going on here.
Any ideas? It could be my VM as it's been running 19.10 for a little
while now.
Hamish
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