[Bug 433394] Re: GRUB loads Windows 7 instead of Bootmenu with default Menu.lst
dino99
433394 at bugs.launchpad.net
Fri Jan 2 16:11:56 UTC 2015
outdated report & no more maintained distro; please send a new one if
that issue still exist (using ubuntu-bug)
** Changed in: grub (Ubuntu)
Status: New => Invalid
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https://bugs.launchpad.net/bugs/433394
Title:
GRUB loads Windows 7 instead of Bootmenu with default Menu.lst
Status in grub package in Ubuntu:
Invalid
Bug description:
Binary package hint: grub
Ubuntu Release: 9.04 Desktop
GRUB Package Version: 0.97-29ubuntu53
I've recently tries out several Windows 7 Versions ( Beta, RC1, MSDN RTM Version ).
After installation i had to reinstall GRUB ( like common if one installs Windows ).
Installation worked fine. Before the Win7 tests i had Vista and used the Vista entries in GRUB's menu.lst.
GRUB loaded Windows 7 but after reboot the Menu wasn't shown.
I've determined that GRUB Activated the Windows 7 Partition.
So i took my Live CD and changed the active flag back to my Linux partition.
And everything worked fine until next Windows 7 boot.
The Problem was the assumption i've could use my Menu.lst with the
Vista entry unchanged.
The Vista entry looked this:
title Windows Vista
root (hd0,0)
savedefault
makeactive
chainloader +1
quiet
I had to disable the makeactive command to get GRUB working as
expected.
So my Win7 entry looks like
title Windows 7
root (hd0,0)
savedefault
#makeactive
chainloader +1
quiet
This solved the problem.
ProblemType: Bug
Architecture: i386
DistroRelease: Ubuntu 9.04
NonfreeKernelModules: nvidia
Package: grub 0.97-29ubuntu53
ProcEnviron:
PATH=(custom, user)
LANG=de_DE.UTF-8
SHELL=/bin/bash
SourcePackage: grub
Uname: Linux 2.6.28-15-generic i686
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