[Bug 1482303] [NEW] python 3.4.0's argparse ignores subcommand

[fish]

Public bug reported:

Hi,

take this simple example:

```
#!/usr/bin/env python3
import argparse

def do_default(options):
    print("default")

def do_build(options):
    print("build")

if __name__ == '__main__':
    parser = argparse.ArgumentParser()
    subparsers = parser.add_subparsers()

    parser.set_defaults(func=do_default)

    build = subparsers.add_parser('build')
    build.set_defaults(func=do_build)

    options = parser.parse_args()
    options.func(options)
```

On Ubuntu 14.04, without parameters it errors for missing command and
with the parameter "build" it prints "default", so the subcommand gets
ignored somehow.

If running this on ubuntu 15.04, it works as expected: Without
parameters, it prints "default". With the parameter "build" it prints
"build".

I couldn't track that to any upstream bug report, but it seems like a
issue was fixed and the fix needs to get backported to ubuntu 14.04.

** Affects: python3-defaults (Ubuntu)
     Importance: Undecided
         Status: New

-- 
You received this bug notification because you are a member of Ubuntu
Foundations Bugs, which is subscribed to python3-defaults in Ubuntu.
https://bugs.launchpad.net/bugs/1482303

Title:
  python 3.4.0's argparse ignores subcommand

Status in python3-defaults package in Ubuntu:
  New

Bug description:
  Hi,

  take this simple example:

  ```
  #!/usr/bin/env python3
  import argparse

  def do_default(options):
      print("default")

  def do_build(options):
      print("build")

  if __name__ == '__main__':
      parser = argparse.ArgumentParser()
      subparsers = parser.add_subparsers()

      parser.set_defaults(func=do_default)

      build = subparsers.add_parser('build')
      build.set_defaults(func=do_build)

      options = parser.parse_args()
      options.func(options)
  ```

  On Ubuntu 14.04, without parameters it errors for missing command and
  with the parameter "build" it prints "default", so the subcommand gets
  ignored somehow.

  If running this on ubuntu 15.04, it works as expected: Without
  parameters, it prints "default". With the parameter "build" it prints
  "build".

  I couldn't track that to any upstream bug report, but it seems like a
  issue was fixed and the fix needs to get backported to ubuntu 14.04.

To manage notifications about this bug go to:
https://bugs.launchpad.net/ubuntu/+source/python3-defaults/+bug/1482303/+subscriptions