Hi, Nevermind. I found it and am using it like this: if (wt.branch.last_revision() != wt.last_revision()): st.append("needs_updating") It does what I need it to now. Cheers. <div class="gmail_quote">On Mon, Jun 15, 2009 at 1:19 AM, Joao Pedrosa <<a href="mailto:joaopedrosa@gmail.com">joaopedrosa@gmail.com</a>> wrote: <blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;"> Hi, When working with Bazaar I try and manage lots of simultaneous branches, sometimes doing operations in a number of them at the same time just to save the trouble to repeat the operation on each one that needs it. So I can for example commit, revert, pull and push in batches. ;-) But when I "update" in batches, I have not found a way to do it only when it's needed to save the unneeded processing of calling it when it's not really needed, but just because it is to work in batch I cannot tell which branch needs it or not and work from there. I tried reading two of the bzrlib files, workingtree.py and branch.py, but I have not found what I wanted. I already make use of Branch.revno for checking the differences so I can push and pull more efficiently, and it seems as if it's the only revno available from what I can tell and it comes from calls to last_revision_info. I once overheard folks saying perhaps on #bzr that there are two revisions, the branch's and the workingtree's or working copy. As far as I can tell, there is no way to retrieve the latter's unless it matches the branch's. ;-) Am I doomed? Having upgraded the format of my branches to "--2a", just for testing it on this desktop computer I checked the time it takes to run update on most of the branches and it took over 3 minutes on this quite fast machine. If there was a way to run update only when it was needed, I could save said minutes and more, as I often run upgrade on the server as well when I push changes to it and want to make use of them for running web sites and so on. I am more worried about scaling this operation so I could grow the number of branches without having to fear further. Cheers and thanks, Joao </blockquote></div>