bzr selftest (on solaris 10): too may open files

[John Arbash Meinel]

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Voelker, Bernhard wrote:
> Vincent wrote:

...

> That means that my python installation most probably uses fopen()
> instead of open() - it is a 32-bit proggy:
> 

Well, according to the earlier parts of this thread, the open handles
are sockets. And I'm pretty sure you can't open a socket with fopen.

So you are looking more for the "socket()" function:

man 2 socket

#include <sys/types.h>
#include <sys/socket.h>

int socket(int domain, int type, int protocol);


You could try exercising that by having a simple server and connecting
to it many times.

For a python example, a server could be:

import SocketServer

num_connections = 0

class MyHandler(SocketServer.BaseRequestHandler):
  def handle(self):
    global num_connections
    num_connections += 1
    print 'Got connect %d from: %s' % (num_connections,
      self.client_address,)
    # Read 10 bytes from the client, just to cause us to block, rather
    # than close the connection right away
    data = self.request.recv(10)

class ThreadedTCPServer(SocketServer.ThreadingMixIn,
                        SocketServer.TCPServer):
  pass

server = ThreadedTCPServer(('localhost', 9999), MyHandler)
server.serve_forever()


And then as a client you could do:

import socket

sockets = []
for i in xrange(10000):
  print 'opening socket %d' % (i,)
  sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
  sock.connect(('localhost', 9999))
  sockets.append(sock)

for sock in sockets:
  sock.send('1234567890')
  sock.close()


On Windows Vista, my SocketServer gets to 1003 connections before it
actually starts failing because of:

Exception happened during processing of request from ('127.0.0.1', 56107)
Traceback (most recent call last):
  File "c:\Python25\lib\SocketServer.py", line 222, in handle_request
    self.process_request(request, client_address)
  File "c:\Python25\lib\SocketServer.py", line 477, in process_request
    t.start()
  File "c:\Python25\lib\threading.py", line 440, in start
    _start_new_thread(self.__bootstrap, ())
error: can't start new thread


John
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