re 0.15rc3/win32: bug report, suggestion and question
Andrew Voznytsa
andrew.voznytsa at gmail.com
Mon Apr 2 14:23:07 BST 2007
Andrew Voznytsa wrote:
> Story continues.
>
> I've PC, let's name it 'host'. There, on disk E, I did:
>
> mkdir e:\repository
> started sshd,
> in cygwin mapped/mounted e:\repository on /repository
> init-repo --no-trees sftp://username@host/repository
> init sftp://username@host/repository/module
> imported some struff
>
> did a lot checkins, checkouts, etc; in two words - worked without any
> problems
>
> After some time I dropped sshd.
>
> shared e:\repository as \\host\repository
>
> now I'm trying
>
> co --lightweight \\host\repository\module somewhere on disk D
>
> works
>
> After that changed something and
>
> ci
>
> and I'm getting
>
> bzr: ERROR: Cannot commit to branch
> BzrBranch5('file://host/repository/module/'). It is bound to
> BzrBranch5('file://host/repository/module/'), which is bound to
> file://host/repository/module/.
>
After examining e:\repository\module\.bzr I found 'bound' file there
which was pointing to branch created from lightweight checkout using
next sequence of commands:
co --lightweight \\host\repository\module 'somewhere on disk D'
cd 'somewhere on disk D'
branch module2
plus there are some records in e:\repository\module\
(e:\repository\module\module2) related to this branch.
Doing 'branch module2' I expected to get local branch which won't be put
in shared repository. Is not that correct?
After some e:\repository\module\.bzr editing commit works as it should.
(P.S. I'm not 100% sure about all commands I typed to create this branch
nor all arguments - it was some time)
>
> NOTE:
> - There was no manual editing any of .bzr files
> - Chekouts were done on the same PC ('host') but in dofferent place.
> - Heavy checkout was in progress some time and failed with
> 'bzr: ERROR: [Errno 22] Invalid argument'
> I guess it was between 1/4 and 2/4 stages
> - Situation is common for 0.14 and 0.15
>
> Could anyone tell me what's wrong?
>
'bzr: ERROR: [Errno 22] Invalid argument' still exists.
Best regards,
Andrew Voznytsa
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